This calculator helps you explore why you feel heavier or lighter in an accelerating elevator. It uses Newton’s laws to find either the apparent weight (scale reading) or the elevator’s acceleration, assuming motion in a vertical shaft near Earth’s surface.
Quick definition: Apparent weight is the normal force a scale exerts on you. In an elevator, that force changes when the elevator accelerates, even though your mass stays the same.
We model a person of mass m standing on a scale in an elevator that accelerates vertically with acceleration a. We choose upward as the positive direction and assume a uniform gravitational field with acceleration g (about 9.8 m/s² on Earth).
The forces on the person are:
Applying Newton’s second law in the vertical direction gives:
Solving for the normal force (apparent weight):
Rearranging the same equation also lets you solve for the elevator’s acceleration when you know mass and apparent weight:
The tool has two modes. In all cases, use SI units (kilograms for mass, m/s² for acceleration, and newtons for apparent weight).
Sign convention reminder: In this calculator, upward is positive. Downward accelerations should be entered as negative numbers, which is important for getting physically meaningful results.
The output tells you how the scale reading compares to your normal weight at rest, mg. You can compare as follows:
| Condition | Math relation | What you feel | Typical scenario |
|---|---|---|---|
| Elevator at rest or constant speed | a = 0, so N = mg | Normal weight | Elevator cruising between floors |
| Accelerating upward | a > 0, so N > mg | Heavier than usual | Lift just starting upward |
| Accelerating downward | a < 0, so N < mg | Lighter than usual | Lift just starting downward |
| Free fall (idealized) | a = −g, so N = 0 | Weightless | Cable failure or drop tower rides (approx.) |
Remember that the calculator reports apparent weight in newtons. To get an equivalent “kg reading” as a bathroom scale might display, divide the result by 9.8 m/s².
Problem: A person has mass 70 kg. An elevator accelerates upward at 2.0 m/s². What is the apparent weight?
Problem: The same 70 kg person stands on a scale in an elevator. The scale reads 560 N. What is the elevator’s acceleration?
You can reproduce both examples directly in the calculator to check your understanding or verify homework solutions.
This calculator is designed for introductory physics and teaching demonstrations. It uses an idealized model with the following assumptions:
Because of these simplifications, the results should not be used for engineering design, safety-critical calculations, or detailed analysis of real elevators. They are most appropriate for conceptual understanding, homework problems, quick checks of intuition, and classroom demonstrations about apparent weight and acceleration.
Awaiting start signal.
Tip: Try loading the calculator with your mass first—the game feeds your inputs into the rider model.