Cryogenic propellants such as liquid hydrogen (LH2), liquid oxygen (LOX), and liquid methane enable high-performance rocket stages and in-space vehicles. Their low temperature, however, makes them sensitive to any heat leak from the environment. Even a well-insulated tank will slowly absorb heat, causing a fraction of the liquid to vaporize and be vented. This loss of liquid mass is called boil-off.
The cryogenic propellant boil-off calculator estimates how much propellant is lost each day and over a chosen storage duration. It uses tank geometry, insulation performance, and basic fluid properties to turn an abstract “heat leak” into concrete mass loss numbers you can factor into mission design, storage logistics, or trade studies.
This tool is intended as a first-order engineering estimate, not a replacement for detailed thermal modeling. It assumes a constant heat leak and uniform conditions, which are often adequate for preliminary sizing, concept studies, and sensitivity analyses.
The calculator is based on a simple energy balance: any heat that leaks into the tank must either warm the propellant or vaporize it. Under the assumption that the propellant remains near its saturation temperature, most of the heat goes into phase change. The rate at which mass is boiled off depends on how much heat arrives at the liquid surface and how much energy is required to vaporize each kilogram of propellant.
The main steps are:
The instantaneous heat leak into the tank is modeled as:
Q = q"" × A
Q is total heat leak into the tank (W).q"" is the average heat flux through the insulation (W/m²).A is the external tank surface area (m²).The energy entering the tank over one day is then:
Eday = Q × 86 400 (J/day)
The latent heat of vaporization is usually given in kJ/kg. Converting to J/kg and dividing gives the daily boiled-off mass:
mday = Eday / L
mday is the mass boiled off each day (kg/day).L is the latent heat of vaporization (J/kg).In expanded form, with latent heat specified in kJ/kg:
Total boil-off over N days is:
mtotal = mday × N
To understand how severe these losses are, the boil-off mass is compared against the initial propellant mass in the tank:
minitial = V × ρ
minitial is the initial mass of liquid propellant (kg).V is the liquid volume in the tank (m³).ρ is the liquid density (kg/m³).The total fraction boiled off over the storage period is then:
fractionboiloff = mtotal / minitial
Multiplying by 100 gives the percentage of the original load that has been lost.
The calculator fields correspond directly to the quantities in the equations above. Typical ranges are indicative and should be adjusted for your specific application.
This is the internal volume actually filled with liquid propellant. It determines the total initial mass stored when combined with the liquid density. For upper-stage tanks, values might range from a few cubic metres up to several tens. Ground storage dewars can be hundreds of cubic metres or more.
The external surface area of the tank through which heat is transferred. Area depends on geometry:
If you do not have an exact area, you can approximate it from design drawings or analytical geometry. The calculator assumes the specified area experiences the stated average heat flux.
This is the average heat flux through the insulation into the tank. It is a lumped representation of all thermal paths (conduction, convection, radiation, supports, penetrations). Representative values include:
The number of days the propellant remains in storage at approximately steady conditions. This might represent coast phases in space, ground holding time before launch, or long-term depot storage scenarios.
The energy required to vaporize 1 kg of propellant at its boiling point without changing temperature. This value is specific to the fluid and its saturation temperature. Typical approximate values at near-atmospheric pressure include:
Use values appropriate to your pressure and temperature conditions when available from datasheets or handbooks.
The density of the liquid phase at the storage temperature. This determines how much mass is stored in each cubic metre of tank volume. Reference values at common conditions include:
Accurate density values help the calculator produce realistic mass fractions, especially for partial fills or off-nominal temperatures.
When you run the calculation, you can expect outputs along the following lines (exact field names may differ):
Small percentages (e.g., < 1% over the full storage period) usually indicate that insulation and tank sizing are adequate for many missions. Higher percentages may signal the need for better insulation, shorter storage times, active cooling, or larger tanks to reduce the area-to-volume ratio.
Consider a liquid hydrogen upper-stage tank with these approximate parameters:
Q = q"" × A = 2 × 200 = 400 W
Eday = 400 × 86 400 ≈ 3.46 × 107 J/day
L = 446 kJ/kg = 446 000 J/kg
mday = 3.46 × 107 / 446 000 ≈ 77.6 kg/day
mtotal = 77.6 × 30 ≈ 2 330 kg
minitial = 100 × 70 = 7 000 kg
fractionboiloff = 2 330 / 7 000 ≈ 0.33, or about 33% of the initial load over 30 days.
This example illustrates how even modest heat fluxes can produce substantial losses over long storage periods, especially for low-density, high-performance propellants like liquid hydrogen.
The table below compares three simplified scenarios using the same 100 m³ hydrogen tank, but with different insulation performance and storage durations. These values are illustrative only; real systems require detailed analysis.
| Scenario | Heat leak q"" (W/m²) | Storage duration (days) | Daily boil-off (kg/day) | Total boil-off (kg) | Boil-off (% of 7 000 kg) |
|---|---|---|---|---|---|
| Minimal insulation | 5 | 10 | ≈ 194 | ≈ 1 940 | ≈ 28% |
| Typical MLI | 2 | 30 | ≈ 78 | ≈ 2 330 | ≈ 33% |
| High-performance insulation | 0.5 | 30 | ≈ 19 | ≈ 580 | ≈ 8% |
Notice how reducing heat flux from 2 W/m² to 0.5 W/m² (a factor of 4) reduces both daily and total boil-off by roughly the same factor. This proportional relationship holds as long as other assumptions remain valid.
The calculator intentionally simplifies the physics to keep the method transparent and easy to apply. Key assumptions include:
Because of these simplifications, the results should be viewed as approximate. They are well suited for quick trades (e.g., “What if I halve the heat leak?”) and concept-level sizing, but detailed mission design should use more comprehensive thermal models or experimental data.
When using this calculator for engineering work or educational purposes, consider the following tips:
For deeper coverage of cryogenic storage and boil-off physics, consider standard references such as cryogenics textbooks, rocket propulsion handbooks, or aerospace thermal design guides from recognized organizations. These sources discuss more advanced topics like stratification, pressure control strategies, and active re-liquefaction systems.