A spacesuit in vacuum cannot dump heat by convection to air. Instead, it mainly exchanges heat by thermal radiation to its surroundings, while the astronaut’s body adds metabolic heat and the Sun (or other sources) can add incident radiation. Most EVA suits also include an active cooling system (for example, a liquid cooling and ventilation garment) that removes a roughly controllable amount of heat.
This calculator estimates a steady‑state (equilibrium) effective radiating-surface temperature for the suit given simple inputs. It is intended for education and rough scenario exploration (e.g., “How much does a whiter outer layer help?”), not mission planning or medical/safety decision‑making.
The model treats the suit as a lumped surface at temperature T exchanging heat by radiation with an environment at T0. The net radiated power is approximated with the Stefan–Boltzmann law:
Absorbed external radiation is modeled as:
Qs = α · F · A
At steady state (equilibrium), incoming heat plus absorbed radiation minus active cooling equals net radiative loss:
Qm + α F A − Qc = σ ε A (T⁴ − T0⁴)
Solving for T:
T = √√( T0⁴ + (Qm + α F A − Qc) / (σ ε A) )
To express the result in Celsius:
T(°C) = T(K) − 273.15
The calculated temperature is best interpreted as an effective radiating surface temperature required for radiation to balance the net heat load under the stated assumptions. It is not a direct prediction of astronaut core temperature, skin temperature under garments, or local hot‑spot temperatures.
If the page displays a “risk score,” treat it as a simple heuristic tied to the computed equilibrium temperature, not a medical probability. Real heat strain depends on many factors (hydration, suit ventilation, work/rest cycles, sensor feedback, and operational constraints). For safety‑critical uses, defer to validated suit thermal models and operational flight rules.
Suppose an astronaut is working moderately hard with:
Absorbed external power:
Qs = α F A = 0.9 × 1361 × 2.0 ≈ 2449.8 W
Net load that must be rejected by radiation:
Qnet = Qm + Qs − Qc ≈ 400 + 2449.8 − 300 = 2549.8 W
Radiative term denominator:
σ ε A ≈ (5.670×10⁻⁸) × 0.8 × 2.0 ≈ 9.072×10⁻⁸ W/(m²·K⁴)
So:
T⁴ ≈ T0⁴ + Qnet/(σ ε A) ≈ 0 + 2549.8 / (9.072×10⁻⁸) ≈ 2.81×10¹⁰
T ≈ (2.81×10¹⁰)^(1/4) ≈ 409 K ≈ 136 °C
This outcome indicates that with very high absorptivity and full solar loading, radiation alone would require an extremely high effective temperature to balance the heat—suggesting that either α must be much lower, the illuminated effective area must be smaller, cooling must be higher, the suit must be oriented/managed to reduce absorbed flux, or the environment differs from the assumed case. This illustrates why reflective outer layers and active cooling are essential.
| Scenario change | What you adjust | Expected effect on equilibrium temperature | Why |
|---|---|---|---|
| More reflective outer layer | Decrease α | Decreases | Less incident radiation becomes heat |
| Higher-emissivity surface | Increase ε | Decreases | Radiates more effectively at a given temperature |
| More active cooling | Increase Qc | Decreases | Reduces net heat that must be radiated away |
| Near warm spacecraft structure | Increase T0 | Increases | Smaller thermal gradient reduces net radiative rejection |
| Higher workload | Increase Qm | Increases | More internal heat to reject |